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Arrange these compounds in order of increasing magnitude of lattice energy: KCl, SrO, RbBr, CaO.
$$\mathrm{RbBr}<\mathrm{KCl}<\mathrm{SrO}<\mathrm{CaO}$$
Chemistry 102
Chemistry 101
Chapter 9
Thermochemistry
Thermodynamics
Chemical reactions and Stoichiometry
Carleton College
Drexel University
Brown University
University of Toronto
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So this problem wants us to place the four compounds K C L as our oh r b b r and C A O in order ofthe increasing magnitude of lattice energy. And so we're going to start with R B B R than K C L than S R O and then CEO. And so the smaller we get, the higher the magnitude of the lattice energy is going to be. And so our B b r is thie Ah, largest and CEO is thie smallest. And so that is how we determined that this is the correct order.
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