Question
Arrange these quantities from smallest to largest in terms of mass: 1.0 mol of $\mathrm{Ar}, 3.0 \times 10^{24}$ atoms of $\mathrm{Ne},$ and 20 $\mathrm{g}$ of $\mathrm{Kr}$ .
Step 1
0 mol of Ar. From the periodic table, we know that the molar mass of Ar is 39.95 g/mol. Therefore, the mass of 1.0 mol of Ar is 1.0 mol * 39.95 g/mol = 39.95 g. Show more…
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Arrange these quantities from smallest to largest in terms of mass: 1.0 mol of $\mathrm{Ar}, 3.0 \times 10^{24}$ atoms of Ne, and 20 $\mathrm{g}$ of $\mathrm{Kr}$ .
Put the following elements in order from smallest to largest mass: (a) $3.79 \times 10^{24}$ atoms Fe (e) 9.221 mol $\mathrm{Na}$ (b) $19.921 \mathrm{mol} \mathrm{H}_{2}$ (f) $4.07 \times 10^{24}$ atoms Al (c) 8.576 mol $C$ (g) 9.2 mol $\mathrm{Cl}_{2}$ (d) $7.4 \mathrm{mol} \mathrm{Si}$
Put the following elements in order from smallest to largest mass: (a) $3.79 \times 10^{24}$ atoms Fe (b) $19.921 \mathrm{mol} \mathrm{H}_{2}$ (c) 8.576 mol $\mathrm{C}$ (d) 7.4 mol $\mathrm{Si}$ (e) 9.221 mol $\mathrm{Na}$ (f) $4.07 \times 10^{24}$ atoms $\mathrm{Al}$ (g) 9.2 mol $\mathrm{Cl}_{2}$
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