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As 1 g of the radioactive element radium decays over 1 year, it produces $1.16 \times 10^{18}$ alpha particles (helium nuclei). Each alpha particle becomes an atom of helium gas. What is the pressure in pascal of the helium gas produced if it occupies a volume of 125 mL at a temperature of 25 °C?

38.276 $\mathrm{Pa}$

01:37

Aadit S.

Chemistry 101

Chapter 9

Gases

University of Central Florida

Rice University

Drexel University

University of Kentucky

Lectures

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So this is another podcast based around the ideal gas equation. So this equation is PV is equal to NRT just for context and so we can rearrange for pressure. My pressure is equal. Thio an r t over V so we can plug in some numbers here. So P is equal to not 0.193 times 10 to the minus five moles. So they're moles that you would have need to calculate. It multiplied by no point No. 8 to 1 atmosphere. Paletta for multi minus one Kelvin's minus juan multiplied by 298 Calvin that is all divided by 9.125 leases. Pressure is equal to study 7.75 775 Now times 10 to the minus five. That was fair. So then we can look at the relationship between past girls and atmosphere. So we have pressure is equal to 77.775 times 10 to the minus five, multiplied by 1013 to 5. Gives us pressure off 38.276 in Pascal's now

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