0:00
Hi there.
00:01
So for this problem, we are told that as a common swings around the sun, eyes on the common surface vaporizes, releasing trap dust particles and ions.
00:10
Now, the ions, because they are electrically charged, are forced by the electrically charged solar wind into a straight ion tailed that points radically away from the sun.
00:23
So the electrically neutral dust particles are pushed radically upward from the sun.
00:30
Sun by the radiation force and then from the sunlight.
00:34
Now we need to assume that the dust particles are spherical and have a density that is equal to 3 .5 times 10 to the 3 kilograms per cubic meter and are totally absorbing.
00:54
So for part a of this problem, we are asked what radius must a particle have in order to follow a straight? path light path to in the figure now let me show the figure in here so this is a situation that we have we have the path to so in order to solve this we shall assume that the sun is far enough from the particle to add as an isotropic point source of light so the forces that add on the dust particle are deradically upward force and the relatively in one force towards the sun, that is the gravitational force.
01:42
So we know that the radically upward radiation force, the radiation force is defined as the intensity of light times the area divided by the speed of light.
01:56
That we can also write as the pressure by the sun divided by four times pi times the radius square and this, well, the power of the sun, of course, and this times pi times the radius squared divided by the speed of light.
02:20
So we can also write this as the power times the radius squared divided by four times the radius square and this times the speed of light.
02:32
Now, capital r in this case is the radius of the particle, and the area is the contraceptional area of that particle.
02:41
On the other hand, the gravitational force on the particle is given by newton's law of gravitation that we know is going to be equal to the gravitational constant times the mass of the sum times the mass of the dust particle, and this divided by the separation distance are to the square.
03:04
So in here we substitute the mass of the dust particle in terms of the density, because we know that that is, the mass can be written in terms of density as the density times the volume.
03:19
So we have this.
03:20
Now we have the density of the dust particle, and this times the volume of the dust particle that is considered as a sphere is this value right here.
03:36
And now we divide this by the separation distance.
03:43
So we can simplify this expression as 4 times pi times the gravitational constant, the mass of the sun, and that times the density of the particle of dots and the radius of the particle to the cube and times three times the separation distance between these two bodies.
04:07
Now, when the two forces balance, we set this to expression equal to each shorter.
04:16
So we will find that this is the power of the sun times the radius squared, divided by four times the separation distance, art to the square times the speed of light...