as-it-is-the-system-above-is-not-balanced-which-of-the-following-changes-would-not-balance-the-syste

Question

As it is, the system above is not balanced. Which of the following
changes would NoT balance the system so that there is o net torque?
Assume the plank has no mass of its own.
(A) Adding a mass equal to $m_{2}$ on the far left side and a mass equal to
(B) Stacking both masses directly on top of the fulcrum
(C) Moving the fulcrum a distance L/3 to the right
(D) Moving both masses a distance L/3 to the left

Vishal Gupta · Accepted Answer

Hi in the given problem a mask less been is he voted at a program? Yeah, like this at the center. Now this beam is divided into four equal parts, each having a length of L. Now there are two particles of masses and one & M. two which will be providing their wits vertically downward and one G. And M two G. At the given points here this is given that and one M two is twice massive As that of M1. Its mouth is twice As that of M one M 2. M one. So the clockwise torque on this bean will be more than the counterclockwise stark. So in the given situation, the clockwise dark acting on this beam will be given by The weight M two G. Multiplied by its perpendicular, transformed the program which is L. And for them to we can use twice off M1 so it becomes twice off. EM Burn G. L. And counter clockwise torque will be given by M one G. multiplied by its botanical distance from the Fulcrum, which is just L. So this is M one G. L. hands. It is clear that the clockwise stock is more than the counterclockwise talk. So this being will be having a tendency to rotate clockwise. Now. In the four given options, we have to make some arrangements. Two bring the beam in equilibrium, rotational equilibrium. Then we have to select the option which will not bring the beam in equilibrium. So here in option a we have to put Hamas, M two At the far left hand means here must M2. So the total counter clockwise torque will come out to be, let it be to one is equal to M two G into perpendicular distance, which will be L plus L means to well. And the original talk Created by the originally present mass and one that is Edwin G. L.. Now as you know, M two equals two twice of heaven. So this is twice of em bong into two L plus M one G L. So it comes out to be five M one GL. No, if you look for the block way start for which there is a mask. I am one that has been placed at the far right end of the beam must them to hear. So now the total clock by Stark will be given by M one G into two L plus the originally present mars was um been in two GL. So finally it comes out to be how to Is equal to four M 1 GL. So as the counterclockwise dot is five MG L. And one jail. And clockwise talk is M one for em and G. So we can say that being is not in a rotational equilibrium. Now, if we look for the option B. Yeah, We are stacking both the masses M1 and M2 directly on the Fulcrum, so doing this, the beam will come and rotational equilibrium, so that being will be balanced. Now, option C. We are moving Fulcrum to the right by L x three here, in this regard, if this fulcrum is shifted towards right here By our the stance of L x three, no other change is made there. So for the clock by stork, Mtg will be multiplied by this distance, which will be L minus Y. Three, and M and G will be multiplied by this distance, which will be L plus L by three. So now the counterclockwise talk will become M one G into L plus L by tree, which will come out to be four M one G. L by three. And counterclockwise and clockwise. Start out too will come out to be M two G into l minus alibi tree for them to again this is two M. One to M one G. Into to L by three again which will come out to be four M one G. L by three. Mr Bean will be balanced in this case. Also now the last case D. This time we are moving both the masses L by three to the left, so doing this, the counter clockwise torque Taiwan will be M one G. And we have shifted it towards the left. So its distance from Fulcrum will be increased by el by three. So it will come out to be four M one G. L x three and clock my store the mass the world Mtg it will be a less distance from the fulcrum. So so it will be l minus L by three and M. Two. We know that is equal to gamble. So the is to mong into L by three. So that is again four M one G. L by three. So again the being will be balanced. Hands only correct option in which the being will not be balanced is option A. Thank you.

Ze-Han Lee · Answer

All right, So in this problem, uh, we have two blocks, so there&#x27;s a fuck room, and the lengths off this sari is too Well, the lens of this side is also too well, and their two blocks is Ah ah, at the center and the mess of the first ones and one and does them too. And we also know that I&#x27;m to equal to everyone. So I want to know that which choice? We&#x27;re not balanced. Uh, we&#x27;re not. Balance the sister. So for parties, is that Adam s equal to m two on the right on the far left side and the mess equal and one the far right side. So that means me at two, we had an to over here and away at I&#x27;m won over here. Okay, so this actually, we&#x27;re not balanced the system, because ah, uh, try to calculate the torque of a system of the new system. So torque induced by end to buy this one is ah to g times to our A and torque induced by this one is a plus and one g times out, and talk induced by this one is Ah, I&#x27;m too g times l the pork induced by this one&#x27;s. I&#x27;m one g times two out Ray and I&#x27;m to equal to M one. So this we&#x27;re not be equal. Okay, so it&#x27;s not Bannister.

Salamat Ali · Answer

center of mass for a two masses can burden his ex cm. Oh, I see him. That is a cool thio x one times in one plus six two x two times in two Derided by Moss one plus master must do so substituting the values Um, we get here. The center of mass for two masses is 0.6 to 5 to fuck Where is the center of mass for three months is seated Can be again, uh can be again found by writing the equation by writing the same thing Only aiding one more extra term which is X three oh, Don&#x27;s Mars free And here in the region who he had one more term plus mastery. So subsidiary lose We get here the news and drop Mars, which is six 0.6 room 16 meters. So this is 160.6 25 meters and the difference we get here is ah, 0.25 meter. So central mass has shifted to the left. By this amount, is there a point 0 to 5 meter to the left? So option is the right answer

R M · Answer

Brooklyn, too. The answer is negative because there is more way to the right and m one waas m two plus N three is equal to 17 then through the rights, and it is equal to 14 which would be using Equation six exporters equal court, 10 times eel plus three times two plus work time. Three months, 14 times six over, then bluffed three plus four plus 14 which is equal to 100 to over 31.

Jayashree Behera · Answer

So all the cheese logs are stated to be stationary so that they are addressed, which means that there is no acceleration and hence there is no net force are the Net force zero, which means that the correct answer is option a.

Ze-Han Lee · Answer

All right, so in this problem, we have a C soul, and here is the fulcrum. So suppose the boys right here and the girl is right here. So the mass of the boys to him and the mess of a girl, he&#x27;s an We want to determine which statement took a balance to cease. All right, so he chose a says that Ah, we move the boy. Ah, to have its original distance from the fulcrum. So this is okay, So suppose we move the boy we&#x27;re here. I use a red pain to draw the new location of the boy. So we get to the ah, the torque exerted by the boys. Ah, two mg to suppose that lens the lens off the sea source out. All right, so two mg times our over four. Because the distance off the board between the boy for a bit in the between the boy and the program is over four. And ah, equal. Aah! Omg times, Albert to write. So m cheese. Damaso is the gravity of the girl. And Elber too. Is that these things from the program to the girl. So we see that the two talks are are equal. So in that sense, the seesaw Spanish and in choice pieces that we move the girl to double her regional distance from the program. So this is also okay, So it says that we move the girl right here. So, uh, this is we say that to the torque exerted by the boys two mg times al over too. And the target exerted by the girl whose mg home salary. So we see that there&#x27;s also equal. So the seats are Spanish and chose CS. Is that Ah, allow a second girl mass them to join the 1st 1 So this is also okay. So suppose we have another girl over here. Please mess in. We see that to the torque exerted by the ah, the boys two mg times that over too right and exited. The target&#x27;s exerted by the two girls are Aah! Omg times out over two plus mg times that over too. Right. So we see that this is also equal. And the choice thesis is that Ah, we moved the fulcrum tohave its original distance from the boy. So this is not okay because ah, we have a new location for the foot room. And here is the boy. And here&#x27;s the girl. So boy, boy boy Mrs to him and the girls masses am we see that at the talk, the talk exerted by the boys two mg times. So because the total total and stuff the seesaws out, ray the distance from the boy to the fulcrum. This case itself divided four. And the distance between the for Graham to the girl is three or four times out. Hurry. So this becomes l&#x27;d by four. And the torque excited by the girl is ah mg times three. They arrive four hell. All right, so you can easily see that the Sorry, this one&#x27;s larger. Okay, so this is of the sea salt. We know people, honest.

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Three identical balls are rolled from left to rig…

Problem 44 Easy Difficulty

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