As shown in Fig. $37-6$, a small luminous body, at the bottom of a pool of water $(n=4 / 3) 2.00 \mathrm{~m}$ deep, emits rays upward in all directions. A circular area of light is formed at the surface of the water. Determine the radius $R$ of the circle of light.
The circular area is formed by rays refracted into the air. The angle $\theta_{c}$ must be the critical angle, because total internal reflection, and hence no refraction, occurs when the angle of incidence in the water is greater than the critical angle. We have, then,
$$
\sin \theta_{c}=\frac{n_{a}}{n_{w}}=\frac{1}{4 / 3} \quad \text { or } \quad \theta_{c}=48.6^{\circ}
$$
From the figure,
$$
R=(2.00 \mathrm{~m}) \tan \theta_{c}=(2.00 \mathrm{~m})(1.13)=2.26 \mathrm{~m}
$$