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Hello.
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In this problem we have two droplets of molten metal splashes.
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Let's call them particles.
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We have two particles that are fired from the same position at the same initial velocity and the same angle, but the only difference is that they are fired at opposite directions.
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And assuming that they both were fired at the same time, we need to get the distance between the two particles as a function in time.
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It's straightforward to guess that the only contribution for their distance will be the horizontal separation between them because both will be at the same height at each point in time because they are moving in sync.
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So let's first get the x position of the first particle, which is the one on the right.
00:56
Let me call this one.
00:57
The x position of it will be just the initial velocity, cosine, theta, multiplied by t.
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And here we assume that the x -axis is to the positive x -axis is to the right.
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So this is for particle number one.
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For the height of this particle as well, we know that as long as they started from the ground.
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So this is just v .i...