Question

As stated in the chapter, potassium superoxide ( $\mathrm{KO}_2$ ) is a useful source of oxygen employed in breathing equipment. Calculate the pressure at which oxygen gas stored at $20^{\circ} \mathrm{C}$ would have the same density as the oxygen gas provided by $\mathrm{KO}_2$. The density of $\mathrm{KO}_2$ at $20^{\circ} \mathrm{C}$ is $2.15 \mathrm{~g} / \mathrm{cm}^3$.

   As stated in the chapter, potassium superoxide ( $\mathrm{KO}_2$ ) is a useful source of oxygen employed in breathing equipment. Calculate the pressure at which oxygen gas stored at $20^{\circ} \mathrm{C}$ would have the same density as the oxygen gas provided by $\mathrm{KO}_2$. The density of $\mathrm{KO}_2$ at $20^{\circ} \mathrm{C}$ is $2.15 \mathrm{~g} / \mathrm{cm}^3$.
 
Show more…
Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 21, Problem 76 ↓
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
As stated in the chapter, potassium superoxide ( $\mathrm{KO}_2$ ) is a useful source of oxygen employed in breathing equipment. Calculate the pressure at which oxygen gas stored at $20^{\circ} \mathrm{C}$ would have the same density as the oxygen gas provided by $\mathrm{KO}_2$. The density of $\mathrm{KO}_2$ at $20^{\circ} \mathrm{C}$ is $2.15 \mathrm{~g} / \mathrm{cm}^3$.
Close icon
Play audio
Feedback
Powered by NumerAI
Ivan Kochetkov Kathleen Carty
David Collins verified

Marissa Turner and 53 other educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Recommended Videos

-
as-stated-in-the-chapter-potassium-superoxide-leftmathrmko_2right-is-a-useful-source-of-oxygen-emplo

As stated in the chapter, potassium superoxide $\left(\mathrm{KO}_{2}\right)$ is a useful source of oxygen employed in breathing equipment. Calculate the pressure at which oxygen gas stored at $20^{\circ} \mathrm{C}$ would have the same density as the oxygen gas provided by $\mathrm{KO}_{2}$ The density of $\mathrm{KO}_{2}$ at $20^{\circ} \mathrm{C}$ is $2.15 \mathrm{g} / \mathrm{cm}^{3}$

Chemistry

7-potassium-superoxide-ko2-is-a-useful-source-of-oxygen-employed-in-breathing-equipment-exhaled-air-contains-moisture-which-reacts-with-ko2-to-produce-oxygen-gas-the-other-products-are-potas-66108

7. Potassium superoxide (KO2) is a useful source of oxygen employed in breathing equipment. Exhaled air contains moisture, which reacts with KO2 to produce oxygen gas. (The other products are potassium hydroxide and hydrogen peroxide.) a) Write an equation for the reaction. b) Calculate the pressure at which oxygen gas stored at 20°C would have the same density as the oxygen gas provided by KO2 . The density of KO2 at 20°C is 2.15 g/cm3

potassium-superoxide-mathrmko_2-is-used-in-some-rebreathing-gas-masks-in-which-the-exhaled-breath-is

Potassium superoxide, $\mathrm{KO}_{2}$, is used in some rebreathing gas masks (in which the exhaled breath is recycled in a closed space). Water vapor in the exhaled air reacts with potassium superoxide to produce oxygen gas: $$ 4 \mathrm{KO}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 4 \mathrm{KOH}(s)+3 \mathrm{O}_{2}(g) $$ In an experiment at $25^{\circ} \mathrm{C}$ and $1.00 \mathrm{~atm}$ in which water vapor reacts with a quantity of potassium superoxide, it was found that $2.70 \mathrm{~kJ}$ of heat was absorbed. The oxygen gas produced was then collected at $23.0^{\circ} \mathrm{C}$ and $789 \mathrm{mmHg}$. What volume (in liters) of oxygen was collected?

General Chemistry


*

Transcript

-
00:01 This is question 81 from tactford 23 and we are trying to find the pressure of potassium super oxide.
00:08 So they give us a density of 2 .15 grams per centimeters cubed.
00:16 So the first thing i do is actually convert this to liters because we're going to be talking about using the ideal gas law.
00:22 So a thousand centimeters cubed is equal to one liter.
00:38 And this is equal to one liter.
00:38 And this is equal.
00:43 To 2 ,150.
00:49 And next we're gonna divide that by the volume.
00:53 And the volume we're gonna assume is that stp, so standard temperature pressure.
00:57 So 2 .150 over, let's you're gonna multiply that with the volume...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever