00:01
So this problem is asking us to draw out the first four periods of an alternate universe's periodic table, where there's a slight difference in the quantum numbers of their orbitals.
00:20
So our s orbital is still going to be holding two, but our p orbital has, um, has two orbits instead of three, so it's only going to be able to hold four electrons, and our d -orbital has three orbits instead of five, so it's only going to be able to hold six electrons.
00:53
And we're being asked to draw out what would that periodic table look like if those were our quantum numbers.
01:00
So what we're looking at here is if we were to draw this out, we would have a 1s1, we would have a 1s2.
01:15
And actually i'm going to move that a little bit further away, just because we're going to need this space, 1s2.
01:27
And then we would have a 2s1, a 2s1.
01:31
A 2s2 and then we would get into our p orbits so then we would have a 2 s 2 2 p 1 2 s 2 2 p 2 2 these a little bit here we would have a 2 s 2 2 p 3 and a 2 s 2 p 4 and that's where it would stop because we would have filled the p shell.
02:24
This one over here.
02:27
1s2.
02:28
If we kept going, our next level would be a 3s1, 3s2, 3s2, 3s2, 3s2, 3p1, 3s2, 3p1, 3s2, 3p2, 3s2, 3p2, 3p2, 3s2, 3s2, 3p2, 3s2, 3s2, 3s2.
02:47
2, 3p4, 3s2, 3p, oops, 3s2, 3p3 here.
02:59
Sorry, skipped a number, and then 3s3p4.
03:03
Then we would get into our fourth period, and this is where we would add in our d -show, so we would have 4s1, 4s2, okay, then we would have, we're going to run out of space here, but we would have 4s2 .3d1.
03:30
4s2, 3d2, 4s2, 3d3, 4s2, 3d3, 4s2, 3d4, 4s2, 3d5, 4s2, 3d5, 4s2, 3d, 4s2, 3d5, 4s2, 3d5, 4s2, 3d, 6 and that fills our d shell because d can only hold 6 and then we would get into our 4 s 2 4p 1 4 s 2 4p 2 4 s 2 4p 3 and 4 s 2 4p 4p 4 so that the messy way of doing it so let's draw it out using boxes and then we can substitute in what those elements are going to be.
04:30
So in our first period, we would have two boxes...