00:02
In this question, we have to find the number of means inserted.
00:09
It is given that sum of two numbers is 13 upon 6 and an even number of arithmetic means are being inserted between them and their sum exceeds their number by 1.
00:28
Let two numbers are a and b.
00:51
Sum of numbers is 2 into 1 upon 6.
01:08
A plus b is equal to 13 upon 6.
01:17
Consider this as equation 1.
01:24
Let a1, a2, a2, a2.
01:41
Ams are inserted between a and b.
02:10
Therefore a, a1, a2, a2n, b are in ap with common difference d is equal to b minus a upon 2 n plus 1 here number of terms in ap is 2 n plus 2 therefore s 2 n plus 2 is equal to 2 n plus 2 is equal to 2 n plus 2 upon 2 into first term plus last term.
03:56
Also s2n plus 2 is equal to a plus a1 plus a2 plus a2 plus a2 plus b is equal to 2 n plus 1 upon 2 into a plus b.
04:30
A1 plus a2 plus a2n is equal to n plus 1 1 into a plus b minus a plus b...