00:01
They want us to assign r or s configuration to the chiral center in each of the following molecules.
00:08
So let's go ahead and start with the one in a we have.
00:13
So in this case, so we already have hydrogen is our lowest priority group.
00:18
So there's no issues there.
00:19
It's already in the back.
00:20
So actually, let's go ahead and draw a mock one just so we can put the numbers down.
00:24
So we have four.
00:26
We have this in the front.
00:28
Like that.
00:28
All right.
00:30
Now, between a sulfur, a carbon, and a carbon, the sulfur has higher priority.
00:36
So our one is going to be facing towards us.
00:38
Then we need to decide, well, what has higher priority? so actually, let's draw this group out.
00:45
So that should be a carboxylic acid.
00:50
And then over here, we just have three hydrogens attached.
00:53
So if we do the little punchout game, notice that, well, we have a hydrogen.
00:58
And then this carbon actually has three.
01:00
Three oxygen's attached to it.
01:02
So because of that, the carbonyl cellc acid is going to take higher priority, so we'd have two there, and then we're going to have three like that.
01:10
So now all we need to do is do our rotation, since our lowest priority group is in the back.
01:16
And so we're going to rotate like this here.
01:20
So the way i like to remember this is, so when you're drawing an r, we would draw it like this.
01:26
And so notice that the curve goes like that.
01:29
So this is going to be to the right for r.
01:34
Or you just remember r is to the right.
01:36
And then for s, a lot of times, or normally, when you draw an s, you start up here, and the rotation goes like that.
01:45
S is going to be to the left.
01:48
So notice over here we're rotating to the left.
01:52
So that means this chiral center here is going to be s.
01:56
Let's go ahead and box that.
01:58
Now for b .e, let's go ahead and draw our little skeleton to start.
02:04
So it's going to be like this here.
02:11
You don't want to do that.
02:13
So like that...