00:01
For this question, we're going to assign relative priorities to the following substituents.
00:05
For part a, we have bromine, iodine, we have a oh and a ch3 or a methyl group.
00:12
So to assign their priorities, we're going to put them in order of increasing atomic number.
00:22
So iodine of these four has the highest atomic number.
00:27
Next is bromine.
00:29
Next, we look at the oxygen, not the hydrogen, because the oxygen will be the atom that is directly attached to the carbon.
00:38
Then last, we have the carbon with the lowest atomic number relative to the others.
00:45
So, in order to order the substituents, we will have iodine, then bromine, then oh, then ch3.
01:02
For part b, we have a two carbon.
01:07
Chain with a oh h at the end, then just an oh, then a ch2 cl, and a ch double bonded to a ch2...