Question
Assume that $10^{12}$ neutrinos passed through every square meter of surface perpendicular to the radiation from Supernova 1987A (which was 160,000 ly away). How many neutrinos were produced by the explosion?
Step 1
First, we need to find the surface area of the sphere with a radius of 160,000 light-years, which represents the distance from Supernova 1987A to Earth. The formula for the surface area of a sphere is A = 4Ď€r^2, where A is the surface area and r is the radius. Show more…
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Supernova $1987 \mathrm{A},$ located about 170,000 ly from the Earth, is estimated to have emitted a burst of neutrinos carrying energy $\sim 10^{46} \mathrm{J}$ (Fig. P15.23). Suppose the average neutrino energy was $6 \mathrm{MeV}$ and your body presented cross-sectional area $5000 \mathrm{cm}^{2} .$ To an order of magnitude, how many of these neutrinos passed through you?
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The neutrino flux from SN 1987 A was estimated to be $1.3 \times 10^{14} \mathrm{m}^{-2}$ at the location of Earth. If the average energy per neutrino was approximately $4.2 \mathrm{MeV}$, estimate the amount of energy released via neutrinos during the supernova explosion.
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