00:01
Okay, so for this point, we're going to differentiate the whole thing with respect to the t, right? so what will get is 6y squared, dy over dt minus 2x, dx over dt, chain rule, and then plus 4, dx over dt.
00:21
This is equal to zero.
00:22
So now we can plug in our values that we're given.
00:25
So we have six.
00:26
Our y, in this case, is just one.
00:29
And remember, we're trying to find dx over dt, or dy over dx.
00:33
Over d t sorry is negative 3 and then we keep so our 2 our x is negative 2 we get our d x over d t because that's the one we don't have and then plus our 4 d x over d t and this equals to 0 so what we'll do here now so 6 times 1 is negative 18 right and i'm actually going to move it to the other side so then we're going to have 4 d x over d t plus 4 dx over dt equals to 18, right? because i get negative here...