00:01
Okay, so in this problem we just need to find what is the ground state energy of the electron and then we have to compare the result to the ground state, connect the energy of the hydrogen atom, in a bar model of hydrogen atom.
00:18
Okay, so first of all, let's calculate what is the ground state energy of the electron.
00:24
Well, we know that since we have the supposition of the particle in a box, we know that that the energy for a particle in a box have discrete values.
00:39
And the formula is just n square, pi square, the plunk constant square, divided by two times the mass of this particle, multiplied by the length of this box.
00:59
Okay? first of all, we have an electron.
01:02
Therefore, the mass of the electron is just 9 .1 times 10 to the minus 31.
01:14
Okay, this is really bad.
01:16
Let's rewrite this.
01:20
We have 9 .1 times 10 to the minus 31 kilograms.
01:32
The second thing we must remember is that the length, the problem gives us, the length of this box, is 2 times 10 to the minus 10 meters.
01:49
Okay, it's two angstons.
01:53
And the final thing we must look in the problem is that we want to find the energy of the ground state.
02:01
The ground state is defined when n equals 1.
02:08
And last, but not least, we have the plunk constant.
02:13
The plunk constant is defined as 1 .054 -57 times 10 to the minus 34 jails...