00:01
Okay, here we have a sequence, square root of 1, and then square root of 1 plus square root of 1, square root of 1 plus square root of 1 plus square root of 1, et cetera, et cetera.
00:12
We are asked to find the limit of the sequence.
00:16
So from here you can probably see the pattern, right? so, a .n plus 1 is equal to square root of 1 plus a .n.
00:27
Right? so you always add one and then take square root.
00:33
So if the sequence converges, then this should stabilize, right? so let's say if limit as n goes to infinity, an is equal to l, l is the limit, then what equation does l has to satisfy? so you can imagine as n goes to infinity, right? this a .n plus 1.
00:59
And an are very close to l.
01:01
So you must have l is equal to square root of 1 plus l.
01:07
And then we just go ahead and solve this equation...