Question

Assume that in Subsection 1c an "ideal" one-stage rocket is considered, which is dropping the unnecessary fraction of its structural mass, (at the moment of complete combustion of the fuel $m_s=0$ ). Using the law of conservation of momentum, show that the maximal speed of such a rocket is determined by the formula $v=(1-\lambda) u \ln \left(m_0 / m_p\right)$. Compare it with the formula (6). Why can the ideal rocket reach any speed?

   Assume that in Subsection 1c an "ideal" one-stage rocket is considered, which is dropping the unnecessary fraction of its structural mass, (at the moment of complete combustion of the fuel $m_s=0$ ). Using the law of conservation of momentum, show that the maximal speed of such a rocket is determined by the formula $v=(1-\lambda) u \ln \left(m_0 / m_p\right)$. Compare it with the formula (6). Why can the ideal rocket reach any speed?
 
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Principles of Mathematical Modelling: Ideas, Methods, Examples
Principles of Mathematical Modelling: Ideas, Methods, Examples
Alexander A.… 1st Edition
Chapter 1, Problem 4 ↓

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In a rocket, we have initial mass $m_0$, payload mass $m_p$, structural mass $m_s$, and fuel mass $m_f$. The structural coefficient is defined as $\lambda = \frac{m_s}{m_s + m_f}$. For an "ideal" rocket, we're assuming that the unnecessary structural mass is  Show more…

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Assume that in Subsection 1c an "ideal" one-stage rocket is considered, which is dropping the unnecessary fraction of its structural mass, (at the moment of complete combustion of the fuel $m_s=0$ ). Using the law of conservation of momentum, show that the maximal speed of such a rocket is determined by the formula $v=(1-\lambda) u \ln \left(m_0 / m_p\right)$. Compare it with the formula (6). Why can the ideal rocket reach any speed?
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Key Concepts

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Conservation of Momentum
This principle states that in the absence of external forces, the total momentum of a system remains constant. In rocketry, as the rocket ejects mass, the loss of mass at high speed results in a reaction force that propels the rocket forward. The conservation of momentum provides the foundation for deriving the rocket’s velocity change during fuel burn.
Tsiolkovsky Rocket Equation
This fundamental equation, developed by Konstantin Tsiolkovsky, quantifies the maximum change in velocity (delta-v) of a rocket as a function of the exhaust velocity and the ratio of initial to final mass. It encapsulates the logarithmic relationship between the mass ratio and the achievable speed, which is central to the analysis of rocket performance and underlies the derivation in the problem.
Ideal Rocket Model
The ideal rocket model assumes that the rocket is designed to discard all non-essential mass (structural mass) during operation, thereby maximizing the efficiency of fuel usage. This concept allows the assumption that the structural mass becomes zero at complete fuel combustion, leading to a theoretically maximized speed. It sets a benchmark for understanding how minimizing dead weight can enhance performance.
Mass Ratio and Logarithmic Dependency
The mass ratio (initial mass divided by payload mass) appears within the natural logarithm in the rocket equation, indicating that the velocity increment increases logarithmically with the mass ratio. This relation means that significant improvements in speed require exponentially increasing the initial mass compared to the payload, which is a critical insight for rocket design and the concept of reaching any speed, assuming structural mass can be minimized.

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A rocket of initial mass M, of which M - m is fuel, burns its fuel at a constant rate k and ejects the exhaust gases with constant speed u. The rocket starts from rest and moves through a medium that exerts the resistance force -kv, where v is the forward velocity of the rocket, and is a small positive constant. Gravity is absent. (a) Show that the velocity at any time t is given by v = u(1 - (M - kt)/M). (b) Find the maximum speed V in terms of γ achieved by the rocket. Note that γ = M. (c) Deduce a two-term approximation for V, valid when γ is small. [Hint: a - x = e^(-xlna) = 1 - xlna + (1/2)(xlna)^2 + O(x^3), for small x.]

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