Question

Assume that the conduction angle of the silicon diodes shown in the circuit of Figure P17.15 is $$ \begin{aligned} & \phi=23^{\circ} \\ & v_{s 1}(t)=v_{s 2}(t)=8 \cos \omega t \quad \mathrm{~V} \\ & \omega=377 \mathrm{rad} / \mathrm{s} \quad R_o=20 \mathrm{k} \Omega \\ & C=0.5 \mu \mathrm{~F} \end{aligned} $$ Determine the rms value of the ripple voltage.

   Assume that the conduction angle of the silicon diodes shown in the circuit of Figure P17.15 is

$$
\begin{aligned}
& \phi=23^{\circ} \\
& v_{s 1}(t)=v_{s 2}(t)=8 \cos \omega t \quad \mathrm{~V} \\
& \omega=377 \mathrm{rad} / \mathrm{s} \quad R_o=20 \mathrm{k} \Omega \\
& C=0.5 \mu \mathrm{~F}
\end{aligned}
$$


Determine the rms value of the ripple voltage.
Show more…
Principles and Applications of Electrical Engineering
Principles and Applications of Electrical Engineering
Giorgio Rizzoni,… 7th Edition
Chapter 17, Problem 15 ↓
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Assume that the conduction angle of the silicon diodes shown in the circuit of Figure P17.15 is $$ \begin{aligned} & \phi=23^{\circ} \\ & v_{s 1}(t)=v_{s 2}(t)=8 \cos \omega t \quad \mathrm{~V} \\ & \omega=377 \mathrm{rad} / \mathrm{s} \quad R_o=20 \mathrm{k} \Omega \\ & C=0.5 \mu \mathrm{~F} \end{aligned} $$ Determine the rms value of the ripple voltage.
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A full-wave rectifier (Fig, 40) uses two diodes to rectify a $95-$ $\mathrm{V}$ rms 60 $\mathrm{Hz}$ ac voltage. If $R=7.8 \mathrm{k} \Omega$ and $C=36 \mu \mathrm{F}$ , what will be the approximate percent variation in the output voltage? The variation in output voltage (Fig. 40 $\mathrm{c} )$ is called ripple voltage. [ Hint: Assume the discharge of the capacitor is approximately linear.]

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00:02 Okay, so the voltage as graphed in the figure decays exponentially.
00:08 V -minim equals v -pick times exponential negative t over tau.
00:12 We rearrange this equation to write the ratio between v -minimum and v -peak to be exponential negative t over tau.
00:19 And then as suggested in the problem, we use the linear approximation.
00:25 Exponential equals 1 minus the t over tau.
00:30 And further, we know this tau is related to the r and c by t equals rc...
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