Question
Assume that the equation defines $z$ implicitly as a function of $x$ and $y$, and use "implicit partial differentiation" to find $\partial z / \partial x$ and $\partial z / \partial y$.$$x-y z+\cos x y z=2$$
Step 1
This gives us: $$1 - yz\sin{xyz} + yz\cos{xyz}\frac{\partial z}{\partial x} = 0$$ Show more…
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