00:04
With these two equations that are showing the elimination of a tertiary iodide using hydroxide as the base, we can write the rate equation for the reaction according to the rate determining step.
00:20
And in equation one, there is just one mechanistic step in which three events take place simultaneously.
00:30
Simultaneously, the hydroxide grabs a proton, sigma electrons become pi electrons, and the iodide leaving group is eliminated.
00:42
So to write the rate equation, the rate constant k times the concentration of the substrate – well, actually, it's all the concentrations of all the reactants in the rate determining step.
01:03
Step.
01:03
So we have the substrate, which is the iodoalkane and the hydroxide base.
01:20
And those are concentration terms are each raised to the first power.
01:28
So if we add the superscripts r1.
01:34
So we add those together and it's second order.
01:40
For the reaction two, the slow step is the rate determining step.
01:56
And the only reactant involved in the rate determining step is the iodo alkane.
02:06
So that's a first order process.
02:19
Now that's significant because because if we wanted to determine which mechanism was operating, we could run the reaction with several different concentrations of hydroxide and see if the rate changes or not.
02:43
If we double the hydroxide concentration and the rate doubles, then equation one describes the mechanism.
02:51
Mechanism.
02:51
But if we double the concentration of hydroxide and the rate remains the same, then equation two describes the mechanism.
03:02
In terms of mechanistic categories, reaction one is an example of an e2 mechanism.
03:11
E is for elimination and two is for bimolecular.
03:15
And then reaction two is an example of an e1 mechanism with e being elimination, one being unimolecular.
03:32
Now for energy diagrams, we have enthalpy on the y -axis and reaction progress on the x -axis...