00:01
So in this problem, we're assuming that the mean body temperature of males is equal to the mean body temperature of females, i'll say women, and alternately that they're different.
00:10
So this will be a two -tail test.
00:14
And our test statistic will end up being the difference between the two temperatures, which is the 93 .68 minus the 98 .17.
00:27
And i'm going to just quick peek at that and make sure i wrote.
00:30
That down right.
00:31
Yeah, it is that.
00:34
98 .17.
00:37
And we have the standard deviation of 1 point, excuse me, 0 .45 squared divided by the sample size of only 15 and the 0 .65 squared divided by the sample size of 91 for females.
00:54
And now we would have this have 14 degrees of freedom before using the conservative estimate.
01:01
And that no pooling and that calculation gives us a t value of negative 33 .33.
01:11
And i missed a three.
01:12
And so we can see that that value is going to give us a p value that is going to be approximately zero.
01:19
It's not zero, but it's very close.
01:21
So the likelihood of getting a t with 14 degrees of freedom being less than, let me get the right symbol here.
01:29
Let's just quick draw a picture.
01:30
I love to see a picture.
01:31
We're assuming.
01:32
The difference is zero, we're getting a difference that is negative, and it corresponds with a t value of negative 33 .33 .3, which means i should have way down here.
01:42
This sum plus this sum, where we go positive 33 .33, with that conservative estimate of 14 degrees of freedom, we would double that, and that would give us our p value, and our p value would be very, very close to zero...