Assume that $Y_{1}, Y_{2},$ and $Y_{3}$ are random variables, with
$$E\left(Y_{1}\right)=2, \quad E\left(Y_{2}\right)=-1, \quad E\left(Y_{3}\right)=4 $$
$$V\left(Y_{1}\right)=4, \quad V\left(Y_{2}\right)=6, \quad V\left(Y_{3}\right)=8$$
$$\operatorname{Cov}\left(Y_{1}, Y_{2}\right)=1, \operatorname{Cov}\left(Y_{1}, Y_{3}\right)=-1, \operatorname{Cov}\left(Y_{2}, Y_{3}\right)=0$$
Find $E\left(3 Y_{1}+4 Y_{2}-6 Y_{3}\right)$ and $V\left(3 Y_{1}+4 Y_{2}-6 Y_{3}\right)$