0:00
Hi there.
00:01
So for this problem, we assume that the angular momentum of the earth of mass that we are given that mass, and that is equal to 6 times 10 to the 24 kilograms.
00:17
Due to its motion around the sun with the radius that is equal to 1 .5 times 10 to the 11 .5 times 10 to the 11.
00:32
Meters to be quantized according to bor's relation, that the angular momentum is equal to n times plums constant h and this divided by two times pi.
00:56
So the question is, what is the value of the quantum number n? so first what we need to know is the definition of the magnitude of the angular momentum.
01:11
We know that that is a problem between the mass, the speed, and the radius.
01:18
Now, we're going to assume that the speed, the orbital speed of the earth is equal to 3 times 10 to the 4 meters per second.
01:35
So if we substitute this expression into here, we're going to have that this is the mass times the speed times the radios and this is equal to n times plums constant and this divided by two times pi so what we are going to do now is to solve for n so the quantum number is two times pi times the mass times the speed times the radios, and this divided by plums constant.
02:12
And now to obtain this value, we just need to simply substitute all of these numerical values...