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This is the answer to chapter 20, problem number three from the mcmurray organic chemistry textbook.
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This problem is a very common organic laboratory problem.
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So if you're taking an organic chemistry course and it has a laboratory component, this is very often the first or second lab that's conducted in the semester.
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So this problem says, assume you have a mixture of naphthalene and benzoic acid that you want to separate.
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How might you take advantage of the acidity of one component in the mixture to affect a separation? okay, so we have a mixture of these two solids.
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They're both just white powders.
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So when they're mixed together, they're impossible to physically separate.
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So what we're actually going to do is what's known as an acid -based extraction.
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So benzodia acid, obviously, is an acid.
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Naphthalene, you know, when you look at it, it's, totally aromatic.
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It doesn't really have any functionality beyond its aromaticity.
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And so we're going to have to do something that takes advantage of the acidity of benzodiaic acid.
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And so basically, the first thing that we would do would be to dissolve both of these solids into an organic solvent.
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So dissolve into, i don't know, let's say, ether.
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Into et2o, so diethyl ether.
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And then once these two solids are dissolved into the ether, what we're going to do is actually add some aqueous base.
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So let's say aqueous sodium hydroxide.
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So a nice strong base.
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And so that's going to deprotonate the benzoic acid.
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So after the addition of aqueous sodium hydroxide, what we will have will be this.
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So the naphthalene is going to be unaffected.
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So it's going to look exactly the same as it did.
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But the benzoic acid is actually going to be in the form of the benzodiae ion.
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So it will look like this.
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So it's been deprotinated.
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And it will be associated with the positive sodium ion...