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Assuming bicycle tires are perfectly flexible and support the weight of bicycle and rider by pressure alone, calculate the total area of the tires in contact with the ground. The bicycle plus rider has a mass of $80.0 \mathrm{kg},$ and the gauge pressure in the tires is $3.50 \times 10^{5} \mathrm{Pa}$ .

$A=2.24 \times 10^{-3} \mathrm{m}^{2}$

Physics 101 Mechanics

Chapter 11

Fluid Statics

Fluid Mechanics

University of Michigan - Ann Arbor

Simon Fraser University

University of Sheffield

University of Winnipeg

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

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Assuming bicycle tires are…

01:08

A person who weighs 625 $\…

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00:45

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The gauge pressure in each…

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See Sample Problem $B.$

04:36

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01:28

(II) The gauge pressure in…

we're told to assume bicycle tires are perfectly flexible and support the weight of the bicycle on writer by pressure alone. So we ought to calculate the total area of the tires in contact with the ground. The bicycle plus writer has a massive 80 kilograms, and the gauge pressure in the tires is 3.5 attended the fifth past gals. So we know our mass of our bike and our rider. You can then figure out the pressure that that we can then use that figure out come the force that's being exerted because we know the pressure in the tire. And so this is good, This f it's going to be the weight of the bike and the writer. So that's just the mass times grab you. And so then we have divided by a which we want a determined. So we know this and we know there's someone could find a so doing that you figure out that a is the weight of the bike and Ryder provided by the pressure in the tires, and we can plug in all those numbers and we get that A is about 0.0 to 2 meters squared or if we convert that into a centimeter square that is 22 centimeters squared for two tires. That seems somewhat large. Actually, maybe the tires are fairly fat, and the pressure is not that high in them.

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