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Assuming Newton's Law of Cooling, suppose soup whose temperature is $190^{\circ} \mathrm{F}$ is poured into a cup in a room whose temperature is $70^{\circ} \mathrm{F}$. Five minutes later the temperature of the soup is $180^{\circ} \mathrm{F}$ (a) What will be the temperature of the soup in another 5 minutes? (b) How long did it take before the temperature of the soup was $150^{\circ} \mathrm{F}$ ?

(e) 0.527 billion(f) $7.9 \times 10^{9}$ billion(a) $170.8^{\circ} \mathrm{F}$(b) 23.3 minutes

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 7

Applications of Exponential and Logarithmic Functions

Campbell University

Oregon State University

McMaster University

Lectures

02:48

Use Newton's Law of C…

11:24

Cooling Soup Suppose that …

03:37

Cooling soup Suppose that …

02:11

A hot bowl of soup is serv…

05:38

05:10

These exercises use Newton…

03:14

Newton's Law of Cooli…

we already know that the mortal function off Newton laws of cooling this do you off is equal to be It bless D not e bowler, my s k b So we are PS is around in temperature The noticed our difference between the initial later than does start learning temperature is the time taken for the cooling door open. So in the given question, given information is that only them But it's 64 degrees father here. So he s is 65 degrees father here That difference just a minute. So let's simplify this. It will become 35 his equal dough 1 45 Ebo minus zero point. You know, for your people So that will be e over minus 0.5 p is equal to 35 by 1 45 So if we apply alone on boats, it's the EPA will go. So we will apply long on both sides. That will give us minus, you know, points. You know, five d is equal to lawn that he forgave by 1 45 so that just be easy. Quarto minus one by 0.5 Indo Lawn 35 by 1 45 So after the simplify it is, he's equal. Do 28 point fourth to the minutes so that their nature 100. If these five need Dr, it'll be just 100 degrees track after to 28.4 30 minutes.

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