Assuming no change in volume, calculate the minimum mass of $\mathrm{NaCl}$ necessary to dissolve $0.01$ mole of $\mathrm{AgCl}$ in $100 \mathrm{~L}$ solution. $K_{\mathrm{sp}}$ of $\mathrm{AgCl}=2.0 \times 10^{-10}$ and $K_{\mathrm{i}}$
of $\mathrm{AgCl}_{2}^{-}=2.5 \times 10^{5}$
(a) $117 \mathrm{~g}$
(b) $11.7 \mathrm{~kg}$
(c) $58.5 \mathrm{~kg}$
(d) $585 \mathrm{~g}$