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Assuming that no equilibria other than dissolutio…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108 Problem 109 Problem 110 Problem 111 Problem 112 Problem 113 Problem 114 Problem 115

Problem 15 Medium Difficulty

Assuming that no equilibria other than dissolution are involved, calculate the concentration of all solute species in each of the following solutions of salts in contact with a solution containing a common ion. Show that changes in the initial concentrations of the common ions can be neglected.
(a) $\operatorname{AgCl}(s)$ in 0.025$M \mathrm{NaCl}$
(b) $\mathrm{CaF}_{2}(s)$ in 0.00133 $\mathrm{M} \mathrm{KF}$
(c) $\mathrm{Ag}_{2} \mathrm{SO}_{4}(s)$ in 0.500 $\mathrm{L}$ of a solution containing 19.50 $\mathrm{g}$ of $\mathrm{K}_{2} \mathrm{SO}_{4}$
(d) $\mathrm{Zn}(\mathrm{OH})_{2}(s)$ in a solution buffered at a pH of 11.45

Answer

a. $7.2 \times 10^{-9} \mathrm{M}$
b. $2.3 \times 10^{-5} \mathrm{M}$, 0.00133 $\mathrm{M}$
c. $2.3 \times 10^{-9} \mathrm{M}$, $1.15 \times 10^{-9} \mathrm{M}$
d. $5.7 \times 10^{-12} \mathrm{M}$ , $2.8 \times 10^{-12} \mathrm{M}$

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Chemistry 102

Chemistry

Chapter 15

Equilibria of Other Reaction Classes

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Chemical Equilibrium

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Video Transcript

starting with auction, eh? We have to equation, which represents disorder ability off e g C l Andi initial along with the initial and equilibrium concentration as followed over here for ages seal and the 2nd 1 represents for an a c l. We all do. We know the expression for Seoul ability constant. That is gai sp equal to concentration off easy, positive while deployed with the concentration off chlorine. Negative. From the first reaction, this one we are already provided. So substituting the values which we have so it will be 1.6 multiplied 10 days to power. Negative 10 is equal to s for Edie. And this less 0.0 to five for glory. We know that the value for s is so small, so as compared to 0.0 to 5. So we can ignore the value off this. So ignoring that we have 1.6 multiplied 10 days to turn negative 10 equals. It's multiplied with little point. Siegel, Go fight rearranging this equation to find the value off Elves. Witches 1.6 Generous tipper Negative. 10 divided by 0.0. Cool. Five. It gives us 6.4 multiply 10 days to one negative nine morning. This will be the concentration for a jeep for the tip by. The concentration for chlorine will be equal to so concentration for chlorine will be equal to 0.0 25 Moving the body be We have to solve all the parts off this question similar in a similar manner. So but be we again have to equation representing the initial and equilibrium concentration. As for fighting the expression for Saul ability again we have gay ESPN equals concentration off culture multiply. But Florian negative ways to power too. Substituting the values We have three point 9 10 days to plan negative 11 equals As my complied with two s last 0.0 13 square. We already know the valuer off s is two small, less compared to 0.13 Rearranging the secretion 3.9 multiple eight and a stupid negative 11 divided by the value off external Toby 2.3 multiplied 10 days to turn negative. Five. This is the concentration off calcium Too positive? Well, for flooring, the concentration is 0.133 Moving too but scene We have initial and equilibrium concentration for a G to s 04 The expression for the concentration off Kato s 04 can be represented us and equals w divided by m multiplied one by being we substitute the values into this formula 19.5 divided by 1 70 4.26 multiplied one divided by 0.5 leaders. The value turned out to be zero point toe 38 morning No moving on to the next equation off gateway so forth the expression for Saul ability again using the GSP expression I'm straight away putting in the values which are one point toe multiplied. Then they stop on negative five equals toe s will square It's a plus zero point 2 to 38 We know the value off s is so small we can ignore it. So the arranging decoration we have s square equals one going toe Multiply 10 days to plan negative five divided by four months plied with 0.22 38 Solving this the value off s turn out to be 6.7 Multiply 10 days to one negative six morning This 6.7 is the concentration off s for do negative by the concentration off 80 positive We have determined earlier as 1.3 multiplied 10 days to try and make it a fight moving toe option d again using the scalability product off said in which to substituting the values we have 4.5 multiply 10 based upon negative 17 equals Yes, do with us 2.8 Multiply tenders to one negative three one square Substituting in the values and rearranging the equation. We have value off s equals 4.5 multiply 10 days to one negative 17 divided by 2.8 12 pretenders to one negative three whole square two the value off Esto No Toby five 0.7. Multiply 10 days to one negative drill. Now we have to determine the concentration off which negative alliance that will be two multiplied with 5.7 10 list of one negative 12 which will be equal to 1.1 10 days toe are negative. 11. This is the concentration off which negative wine by 5.7 represents the concentration off zinc. Was it divine that into positive

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Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson

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