00:01
So here we're taking a look at retro -synthetic reactions.
00:04
We're essentially given a target molecule and we're just having to work backwards.
00:08
So we take a look at our first structure, make our synthetic cut, draw our retro synthesis arrow, and now we draw our components, where we have two methyl, propan -one -ol and bromobenzene.
01:06
So sort of reagents that we're going to be needing here is we're going to be needing mg and et -2o for this conversion to get to, phenyl magnesium bromide.
01:18
You need pcc and ch2 cl2 to get from our alcohol to our aldehyde.
01:26
Then we react these two together in the presence of et2o and h3o plus of proton source.
01:35
Then in the second step we have pcc and ch2 cl2.
01:40
So in the next example we have we can make two synthetic cuts.
02:37
It's moving straight on to our next example just to say very of time here we've already discussed the sorts of reagents that we need for these types of chemical reactions so all we're going to be focusing on is the structures themselves to make our synthetic cut green yard reagent and this is generated using a alcohol starting material and our other starting material also contains an alcohol so we're just chemically transforming our starting target molecule that we have into a primary alcohol because we can achieve this chemical transformation here in reverse.
04:08
Then we can make our chemical cut.
04:13
Now we can think about drawing our starting materials.
04:37
One of our starting materials is an epoxide.
04:47
We just insert a new page.
04:52
Moving on to our next example here.
05:13
And first have a chemical transformation into an alcohol, then we make a new page.
05:22
Make our synthetic cut.
05:25
Now we'll draw our materials and an epoxide.
05:37
Well we've seen this step before we go from magnesium bromide to just a bromide containing molecule and then we use the alcohol form...