Assuming the standard model coupling, show that
$$
\Gamma\left(Z \rightarrow \nu_{e} \bar{\nu}_{e}\right)=\frac{g^{2}}{96 \pi \cos ^{2} \theta_{W}} M_{Z}
$$ see Exercise 13.2. Given that $\sin ^{2} \theta_{W}=0.25$ and $M_{Z}=90 \mathrm{GeV}$, predict the numerical value of the partial width.