00:01
In the discussion of apparent magnitude where the magnitude of venus is negative 4 .4, while the magnitude of sirius is negative 1 .4, venus is brighter.
00:21
In the magnitude system, the more negative something is, the brighter it is.
00:28
We can write this as a logarithmic relationship where m is equal to k log b, where m is the magnitude, b is the actual brightness of the object, and k is some constant.
00:52
Then taking a ratio, m2 minus m1 is k times the log of b2 minus the log of b1.
01:08
By the property of logarithms, this is k times the log of b2 over b1.
01:21
We could go ahead and solve for k knowing the ratio of brightnesses knowing that a change in magnitude of 5 corresponds to a brightness ratio of 100 so we can say k equals m2 minus m over the log of b2 over b1, which is 5 over the logarithm of 0 .01.
02:12
Sorry, i mixed these up.
02:16
B2 over b1 should be 1 over 100.
02:27
This gets us a k of negative, 2 .5.
02:34
So our equation is m equals minus 2 .5 logarithm of b...