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At $20^{\circ} \mathrm{C},$ the vapor pressure of water is 0.0231 atm. Calculate $K_{P}$ and $K_{\mathrm{c}}$ for the process$$\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(g)$$

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$$\begin{array}{l}K_{p}=0.0231 \\K_{c}=9.60 \times 10^{-4}\end{array}$$

Chemistry 102

Chapter 14

Chemical Equilibrium

Carleton College

Rice University

University of Maryland - University College

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

01:38

The vapor pressure of wate…

01:39

02:26

At $25^{\circ} \mathrm{C}$…

02:17

02:03

01:00

At a temperature of $60^{\…

02:22

So for the falling balanced equilibrium we want to find V, K, p and the Casey values. So when we're thinking about Cape, he first of all, we know that k p iss the equilibrium constant in regards to partial pressure and this equilibrium constant Onley taste into account substances in the gaseous form. Instance, we only have one substance in the gaseous form, and that is our product and it's water vapor. And we were told that the partial pressure of H 20 was 0.0 231 a t m. Equilibrium. We can say that the KP it's equivalent the partial pressure of our Onley gaseous substance at equal around. So now that we have the KP, we could use fallen equation to find the Casey or equilibrium Constant regards concentration value. So we want to look at what we have. We know the temperature we were told that was 20 degrees Celsius. And if you add 273 to convert to Calvin, we get 293 degrees kelvin and then for moles. We have one mole off gases product and no moles of gaseous reacting. So this is just one. So that means we can go ahead and put all this in first. We're gonna use our KP value that we found using the partial pressure off Fox. I mean of water. But then we want to know what Casey is. Are is the ideal gas. Constance. That's something that we know times the Calvin temperature that we found raised to a power of one. So you'll find that K C is equivalent to this. Simplified down a little bit so we can see how we're getting our answer. And this is a whole went to 9.6 times 10 negative for And this is our Casey or equilibrium constant regards to concentrations about you.

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