At 298 K, ΔG^∘=+11.51 kJ for the reaction CaF2( s) ⇌Ca^2+(aq)+2 F^-(aq) (a) Calculate ΔG at t

step 1 So in this problem, we're asked to calculate the change of gives free energy at 298 Kelvin. If w

At 298 K, ΔG^∘=+11.51 kJ for the reaction CaF2( s)...

At $298 \mathrm{~K}, \Delta G^{\circ}=+11.51 \mathrm{~kJ}$ for the reaction $$ \mathrm{CaF}_{2}(\mathrm{~s}) \rightleftharpoons \mathrm{Ca}^{2+}(\mathrm{aq})+2 \mathrm{~F}^{-}(\mathrm{aq}) $$ (a) Calculate $\Delta G$ at the same temperature when $$ \left[\mathrm{Ca}^{2+}\right]=3.5 \times 10^{-2} M \text { and }\left[\mathrm{F}^{-}\right]=2.3 \times 10^{-3} \mathrm{M} $$ (b) Under the conditions in part a, in which direction is the reaction spontaneous?

At $298 \mathrm{~K}, \Delta G^{\circ}=+11.51 \mathrm{~kJ}$ for the reaction
$$
\mathrm{CaF}_{2}(\mathrm{~s}) \rightleftharpoons \mathrm{Ca}^{2+}(\mathrm{aq})+2 \mathrm{~F}^{-}(\mathrm{aq})
$$
(a) Calculate $\Delta G$ at the same temperature when
$$
\left[\mathrm{Ca}^{2+}\right]=3.5 \times 10^{-2} M \text { and }\left[\mathrm{F}^{-}\right]=2.3 \times 10^{-3} \mathrm{M}
$$
(b) Under the conditions in part a, in which direction is the reaction spontaneous?

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Gibbs Free Energy

Gibbs free energy is a thermodynamic potential that indicates the capacity of a system to do work at constant temperature and pressure. It is used to predict whether a chemical reaction will proceed spontaneously; reactions with negative ?G are spontaneous whereas those with positive ?G are non-spontaneous.

Standard Gibbs Free Energy Change (?G°)

This is the change in Gibbs free energy when reactants and products are in their standard states. ?G° serves as a reference point and is related to the equilibrium constant, allowing the calculation of free energy changes under varying conditions.

Reaction Quotient (Q)

The reaction quotient is a dimensionless number that compares the current concentrations or pressures of the reaction species to the stoichiometric coefficients specified in the balanced reaction. It provides a snapshot of the reaction progress and is essential for determining how far a system is from equilibrium.

Gibbs Free Energy under Non-standard Conditions

The equation ?G = ?G° + RT ln Q is used to calculate the free energy change under non-standard conditions by incorporating the effects of current concentrations or pressures. This relationship shows how deviations from the standard state influence the spontaneity and direction of a reaction.

Transcript

Please give Ace some feedback