0:00
Hi there.
00:02
So for this problem we are given that the horizontal component of the electric field vector it's equal to 2 .3 times the vertical component of the electric field vector.
00:25
Now with this condition and also the information that the glasses eliminate the horizontal field component so that we know that the initial one is a combination, well, the square of the initial one is a combination of the horizontal component square plus the vertical component square.
00:52
But since the glasses eliminate the horizontal field component, then the final electric field square is going to have only the vertical component.
01:10
So with that said, for part a of this problem, we need to find the fraction of the light intensity receive before the glasses were put on and now that the glasses, and now that they are put in the sunbatter's eyes.
01:34
So with that said, we need to calculate the final intensity over the initial intensity.
01:42
Now, the intensity is proportional to the electric field vector.
01:54
Now, we are going to have then that this, well, the square of the electrode field.
02:00
So we are going to have that this is equal to the electric, the, the, final electric fuel square over the initial electric fuel square.
02:11
So we know, as we said from the beginning, that the final one only has the vertical component.
02:25
Meanwhile, the initial one has the horizontal component and the vertical component.
02:32
But we now use the condition that we are given we know that the horizontal component is 2 .3 times the vertical component.
02:46
We elevate that to the squared plus this...