Question
At a distance of $16 \mathrm{~m}$ from a charged particle, the electric field has a magnitude of $100 \mathrm{~N} / \mathrm{C}$. (a) At what distance is the electric field $400 \mathrm{~N} / \mathrm{C} ?$ (b) At what distance is it $10 \mathrm{~N} / \mathrm{C} ?$
Step 1
Step 1: We know that the electric field produced by a point charge is given by the formula $E = \frac{kQ}{r^2}$, where $E$ is the electric field, $k$ is Coulomb's constant, $Q$ is the charge, and $r$ is the distance from the charge. Show more…
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