00:01
Here we have a following situation.
00:02
A particle of a given mass is moving in a positive y direction with the velocity v given.
00:12
And there is a magnetic field given in the problem, b acting in a negative x -6 direction.
00:22
We label the positive y direction with the unit factor that is j -cap and minus i cap, or, will be the unit vector in a minus x direction.
00:35
For part a of the problem, the magnitude of force will be equal to qv cross b times a sine theta.
00:45
Theta is the angle between the particle v and a b.
00:51
So substituting your values, we get the force to be 3 .50 times 10 to the power minus 8 times 2 times 10 to the power 5 meter per second times 0 .8 tesla times the angle we have here is a 90 degrees.
01:08
So 90.
01:10
So substituting a value for a 90 degrees.
01:13
We get the force, force of 5 .6 times 10 to the power minus 3 newton...