00:02
Let's first for part a, let's start with an ice table.
00:11
And we'll fill in our known details.
00:14
We're told that we have, flask contains only in 204 at an initial pressure of four and a half atmospheres.
00:26
It's filling the rest of the ice table.
00:31
And our kp expression here is going to be, the partial pressure of n02 squared over the partial pressure of n204.
00:47
And we have the kp given to us is 0 .25, and this is equal to 2x squared over 4 .5 minus x.
01:02
We do get a quadratic equation here.
01:06
So going ahead and solving for x.
01:11
I'm going to go ahead and solve and you can verify that your solution is the same as mine.
01:24
2x squared in the numerator, 4 .5 minus x in the denominator.
01:31
Solving for x here is going to give me we have two roots.
01:38
I'm only going to take the positive root.
01:41
So going back to the ice table, the equilibrium values of n204 is 4 .5 minus x.
01:53
So this would be 4 .0 0 atmospheres and 2 times x would be 1 .0 atmospheres.
02:00
So those are the equilibrium concentrations for n204 and n02.
02:07
For part b, let's also start by creating an ice table...