Question
At a party there are 15 men and 20 women.(a) How many ways are there to form 15 couples consisting of one man and one woman?(b) How many ways are there to form 10 couples consisting of one man and one woman?
Step 1
There are 20 women to choose from for the first man, 19 for the second man, 18 for the third man, and so on. So, the total number of ways to form 15 couples is: 20 * 19 * 18 * ... * 6 = 20! / 5! = 2,432,902,008,176,640,000 / 120 = 20,353,450,068,976 ways. Show more…
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