00:01
Hi, in the given problem, the spring factor of the given spring is 40 newton per centimeter, or it will become 40 into 100 newton per meter means 4 ,000 newton per meter.
00:21
Mass of the sledge with the rider is 70 kilogram.
00:26
In the first part of the problem, when the spring is compressed to a distance of 0 .375 meter, then the kinetic energy gained by the sledge will be equal to elastic potential energy stored in the compressed spring.
01:09
So we can say this is half m v square is equal to half k x square.
01:17
Cancelling this half, we get an expression for v, which is given as x square root of k by m.
01:28
So plugging in the known values, the value of v comes out to be for x.
01:35
This is 0 .375 meter square root of 4 ,000 newton per meter divided by mass which is 70 kilogram.
01:49
So finally, this value of the speed achieved by the sledge comes out to be 2 .83 meter per second and it becomes the answer for the first part of the problem now.
02:04
In the second part of the problem, it is said that spring is still compressed by 0 .200 meter.
02:15
And initially it was compressed by 0 .375 meter.
02:20
So now we have to find the speed achieved by the velocity achieved by the sledge.
02:26
When the spring is still compressed by 0 .200 meter...