At modest pressures the equation of state of a gas can be written as $p V=R T+B p$, where $B$ is a function of $T$ only. (i) Find an expression for the Joule-Kelvin inversion temperature in terms of $B$ and $\mathrm{d} B / \mathrm{d} T$. (ii) For helium gas between $5 \mathrm{~K}$ and $60 \mathrm{~K}, B$ can be represented as $B=m-(n / T)$, where $m=15.3 \times 10^{-6} \mathrm{~m}^3 \mathrm{~mole}^{-1}$ and $n=352 \times 10^{-6} \mathrm{~m}^3$ $\mathrm{K} \mathrm{mole}{ }^{-1}$. From this information, estimate the inversion temperature for helium. For an expansion starting below the inversion temperature, comment on the efficiency of the process (i.e. cooling per unit pressure change) as the temperature falls. (iii) In a helium liquifier, compressed helium gas at $14 \mathrm{~K}$ is fed to the expansion valve, where a fraction $x$ liquifies and the remaining fraction $(1-x)$ is rejected as gas at $14 \mathrm{~K}$ and atmospheric pressure. If the specific enthalpy of helium gas at $14 \mathrm{~K}$ is given by
$$
h=a+b\left(p-p_0\right)^2
$$
where $a=71.5 \mathrm{~kJ} \mathrm{~kg}^{-1}, b=1.3 \times 10^{-12} \mathrm{~kJ} \mathrm{~kg}^{-1} \mathrm{~Pa}^{-2}$, and $p_0=3.34 \mathrm{MPa}$ $(=33.4 \mathrm{~atm})$, and the specific enthalpy of liquid helium at atmospheric pressure is $10 \mathrm{~kJ} \mathrm{~kg}^{-1}$, determine what input pressure will allow $x$ to achieve a maximum value, and show that this maximum value is approximately 0.18 .