At t=0 a 1.0 kg ball is thrown from a tall tower with v⃗=(18 m / s) î+(24 m / s) ĵ. What is Δ

Name: Problem 25, Chapter 8: Fundamentals of Physics
Uploaded: 2020-01-01T14:51:45-08:00
Duration: 1 min 38 s
Channel: Farhanul Hasan
Description: At t=0 a 1.0 kg ball is thrown from a tall tower with v⃗=(18 m / s) î+(24 m / s) ĵ. What is ΔU of the ball-Earth system between t=0 and t=6.0 s (still free fall)?

step 1 All right, so we're given a velocity, we're given a velocity in terms of, with the x and y compo

Question

At $t=0$ a $1.0 \mathrm{~kg}$ ball is thrown from a tall tower with $\vec{v}=(18 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}$. What is $\Delta U$ of the ball-Earth system between $t=0$ and $t=6.0 \mathrm{~s}$ (still free fall)?

   At $t=0$ a $1.0 \mathrm{~kg}$ ball is thrown from a tall tower with $\vec{v}=(18 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}$. What is
$\Delta U$ of the ball-Earth system between $t=0$ and $t=6.0 \mathrm{~s}$ (still free fall)?

Fundamentals of Physics

David Halliday,… 10th Edition

Chapter 8, Problem 25

Instant Answer

Solved by Expert Farhanul Hasan

01/01/2020

Step 1

First, we need to find the final velocity of the ball at t=6.0 s. To do this, we can use the kinematic equation for the vertical motion: vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration due to gravity, and t is the Show more…

Show all steps

Thanks for your feedback!

At $t=0$ a $1.0 \mathrm{~kg}$ ball is thrown from a tall tower with $\vec{v}=(18 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}$. What is $\Delta U$ of the ball-Earth system between $t=0$ and $t=6.0 \mathrm{~s}$ (still free fall)?

Play audio

Feedback

Farhanul Hasan and 61 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Gravitational Potential Energy

This concept refers to the energy an object has because of its position in a gravitational field. The change in gravitational potential energy is calculated using the product of mass, the acceleration due to gravity, and the vertical displacement of the object, regardless of its horizontal motion.

Kinematics Under Constant Acceleration

This area of mechanics studies the motion of objects when they are subject to a constant acceleration, such as that provided by gravity. It is used to determine the vertical displacement of an object over time, using initial velocity, acceleration, and time in the kinematic equations.

Vertical Displacement

This is the change in the vertical position of an object over time. In the context of gravitational potential energy, it is the key variable that, when multiplied by mass and gravitational acceleration, gives the change in potential energy.

Please give Ace some feedback