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At the beginning of a basketball game, a referee tosses the ball straight up with a speed of 4.6 $\mathrm{m} / \mathrm{s}$ . A player cannot touch the ball until after it reaches its maximum height and begins to fall down. What is the minimum time that a player must wait before touching the ball?
0.47$s$
Physics 101 Mechanics
Chapter 2
Kinematics in One Dimension
Motion Along a Straight Line
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So Problem 76 has a basketball that's being thrown upwards, Um, getting our starting information down here. Its initial speed is 4.6 meters per second. It is being thrown on the planet Earth, so it's acceleration is negative, 9.8 meters per second squared and its final velocity when it reaches the top of being thrown up is zero meters per second. Now when the ball reaches the top of its arc is the first time a player would be allowed to touch it. So this question is asking, How long would a player have to wait before they touch the ball? Now, this is a case where we know our 1st 3 variables. We're looking for the time, so we don't know X and we don't need to know X. So to solve this problem, I'd be looking for my equation. That does not have X, which is that 1st 1 the equals B not plus 80. And when I plugged, my number's in here we get zero equals 4.6 minus 9.8 t, which will me swing this over ends up with a time of 0.47 seconds is how long you'd have to wait before touching that ball in a game of basketball
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