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At the end of Example $27.8,$ it was stated that the intensity of polarized light is reduced to 90.0$\%$ of its original value by passing through a polarizing filter with its axis at an angle of $18.4^{\circ}$ to the direction of polarization. Verify this statement.

Therefore, the intensity of light after passing through the filter is 90$\%$ of original intensitybefore passing through the filter.

Physics 103

Chapter 27

Wave Optics

Cornell University

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University of Sheffield

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Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

00:41

If you have completely pol…

02:08

$\bullet$$\bullet$ Plane-p…

05:21

You use a sequence of idea…

01:56

A beam of polarized light …

02:56

Light of original intensit…

00:57

What angle would the axis …

07:26

(III) Describe how to rota…

00:49

01:04

01:28

Show that if you have thre…

01:27

$\bullet$$\bullet$ A beam …

02:29

$\bullet$ Light of origina…

0:00

00:34

What angle is needed betwe…

01:12

00:28

The angle between the axes…

02:24

Unpolarized light with i…

01:09

Prove that, if $I$ is the …

01:33

If a polarizing filter red…

03:17

PolarizationA beam of …

let the polarized light we have his eye dog. And after the filter, uh, reduces Thio. The port 10% off I nod was 90% is observed. So this game Burton, is 0.21 My lord, that is it called to the initial intensity of course square. Then we can find that their time from here by canceling out this is this so they dough becomes their days equal. Do 71.6 degrees. We can verify this by writing. Hi is according to my nod, um then of course, square course, we're 90 minus so 90 minus 71. According to what? Her six degrees this gives us the eye is equal to intense after Phil trees. I know that is, of course, square off 18.4 degrees. So coarse square off 18.40 years gives us, um I know these times zero point mine, which is a 90% 90% off. I know, I know

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