At the end of Section 9 we proved that if $\mathrm{H}$ is a Hermitian matrix, then the matrix
$e^{i \mathrm{H}}$ is unitary. Give another proof by writing $\mathrm{H}=\mathrm{CDC}^{-1},$ remembering that now C is unitary and the eigenvalues in $D$ are real. Show that $e^{i D}$ is unitary and that
$e^{i \mathbf{H}}$ is a product of three unitary matrices. See Problem $9.17 \mathrm{d}$