00:02
Hi, in the given problem here, this is the tank in which there is a coil.
00:21
The coil is having the number of turns given as n is equal to 100.
00:39
Diameter of the circular tank is given as 1 .2 meter so its radius r will be half of the diameter means it's 0 .6 meter the magnetic field earth's magnetic field here is b is equal to 50 microtesla at an angle of dip equals to 56 degree and here the angle of dip means if you consider it to be here, this is the earth's magnetic field.
01:29
Then the angle of dip means the angle made by earth's magnetic field with the horizontal in downward direction.
01:38
Delta is angle of dip.
01:40
So there will be two components of earth's magnetic field.
01:45
Horizontal component bh and vertical component.
01:51
Meant bv.
01:55
Now if we pass a current i through the coil, suppose the current passing through the coil is i due to which as here it is given that the angle of dip should be increased to 62 degree and the horizontal component of earth's magnetic field will remain same as bh, means which was given as b, cos, delta.
02:46
So in order to increase the angle of dip, the total vertical component should be increased.
02:55
Net vertical component of magnetic field should be increased to bv dash, which will be equal to the original vertical component plus the magnetic field produced by the coil.
03:18
So it is bv plus b coil using the expression for angle of dip which is given in terms of tangent...