00:02
The car's position is a function of time given by one half, since its acceleration, which is 2 .80 meters per second squared, times times squared.
00:21
The truck's position, since it has no acceleration, simply its velocity, which is 20 .0 meters per second times time.
00:37
Now to find the point where the car catches up to the truck, we set the car's position equal to the truck's position.
00:46
X of car is equal to x of truck.
00:54
And solving for t, we get the time of intersection, 14 .29 seconds.
01:08
We wanted to find the distance that the car travels before it catches up to the truck.
01:13
Now we take this time, plug it back into our position equation for the car, and we find that the distance of the car travels before it catches up to the truck is equal to 200 and 86 meters.
01:33
So that's part a.
01:39
Now part b asked us to find the final velocity of the car once it's hot up to the truck.
01:48
Find that we simply use vf as equal to b initial plus a times c.
01:58
Of course the car's initial velocity was zero.
02:01
Final velocity is simply just going to be its acceleration times the time we found in part a and was 14 .29...