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At the measured frequency, what is the ratio of the capacitivereactance of a typical clavus sample to that of verruca?\begin{equation}\begin{array}{llll}{\text { A. } 0.21} & {\text { B.4.9 }} & {\text { C. } 16} & {\text { D. } 110}\end{array}\end{equation}
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Physics 102 Electricity and Magnetism
Chapter 24
Alternating-Current Circuits
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Electromagnetic Induction
Alternating Current
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the capacity reactor's off the clavicles X C seed is equals to one. Divide it by two pi times the frequency times the past tense about the gravel's. Similarly, the capacity reactors of America is it close to one divided by two pi times the frequency times the capacitance off Veruca. Then they reach you. X C See divided by X C V. Easy clothes, too, to pi times the frequency times CV divided by two pi times the frequency plying cc simply find common terms. We get CV over CC, which is equal to five 0.859 of for its divided by one or two none of pirates and this is approximately 4.9, then the correct alternative to that question is be.
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The number 2 is also the smallest & first prime number (since every other even number is divisible by two).
If you write pi (to the first two decimal places of 3.14) backwards, in big, block letters it actually reads "PIE".
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