00:01
High in the given problem, the potential applied across an lr circuit, a series lr circuit is given as 45 volt.
00:18
The value of inductance of this circuit is 50 millie henry and the value of resistance the same 1080 om.
00:35
We have to find the time rate of change of current which is passing through this lr circuit at a time t which is given as 1 .2 milliseconds or this is 1 .2 into 10 dash for minus 3 second.
00:54
So to find this time rate of change of current, and we will use the equation of current as a function of time.
01:06
After switching on this circuit, lr circuit, the current will be growing as per the function i is equal to i0 bracket 1 minus e raise to the power minus t by tau, where i .0 is the maximum equilibrium current passing through the circuit which will be given by v by r and this tau is the time constant of this lr circuit and that is given as l by r.
01:45
Now differentiating this equation with respect to time we get an expression for the time rate of change of current with the passage sorry the time rate of change of current with respect to time and that is given as d .i.
02:01
D.
02:01
T is equal to differentiation with respect to time of the function i .0, 1 minus e rase to the power minus t by tau...