Question
At what frequency is the output of the circuit of Example 5.6 attenuated by 10 percent (that is, $V_o=0.9 V_i$ )?
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An alternating voltage $V_{0} \cos \omega t$ is applied to the terminals at $A$. The terminals at $B$ are connected to an audio amplifier of very high input impedance. (That is, current flow into the amplifier is negligible.) Calculate the ratio $\left|V_{1}\right|^{2} / V_{0}^{2}$. Here $\left|V_{1}\right|$ is the absolute value of the complex voltage amplitude at terminals $B$. Choose values for $R$ and $C$ to make $\left|V_{1}\right|^{2} / V_{0}^{2}=0.1$ for a $5000-\mathrm{Hz}$ signal. This circuit is the most primitive of "low-pass" filters, providing attenuation that increases with increasing frequency, Show that, for sufficiently high frequencies, the signal power is reduced by a factor $/ / 4$ for every doubling of the frequency, Can you devise a filter with a more drastic cutoff -such as a factor $1 / 6$ per octave?
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