00:02
Okay, so we're working with benzeneylyde here.
00:05
You'll notice that there are two rings.
00:07
So we have to determine which ring and at what position on that ring would bromination occur at.
00:14
So it doesn't matter which electrifier we're adding.
00:15
It matters what we're dealing with what substituents are already on the ring.
00:20
So let's take the ring on the left first.
00:23
The ring on the left only has one substituent and there is a carbonyl on the carbonial on the carbon that's right next to the ring.
00:28
Therefore we're going to have a strong electron withdrawing group on that ring.
00:33
This ring is going to be deactivated because of that carbonyl group.
00:37
So we're off to a good start.
00:40
The ring on the right, even though it is bridged by this carbonyl containing group, the carbonyl isn't adjacent to the ring.
00:51
And that makes a huge difference about the electronics of that ring.
00:55
In fact, because the nitrogen is the group that is, adjacent to the second ring on the right, you actually have an electron donating effect from that nitrogen.
01:07
So although this carbonyl is going to be electron withdrawing overall, you do get some degree of stabilization from the lone pair on that nitrogen.
01:18
So it's somewhat equivalent.
01:20
It's not as good.
01:21
Let's say this was a methyl group instead of a carbonyl.
01:24
The ring on the right would be more activated...